3.6.24 \(\int (d+c^2 d x^2)^{5/2} (a+b \text {arcsinh}(c x))^n \, dx\) [524]

3.6.24.1 Optimal result

Integrand size = 25, antiderivative size = 632 \[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\frac {5 d^2 \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^{1+n}}{16 b c (1+n) \sqrt {1+c^2 x^2}}+\frac {2^{-7-n} 3^{-1-n} d^2 e^{-\frac {6 a}{b}} \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac {6 (a+b \text {arcsinh}(c x))}{b}\right )}{c \sqrt {1+c^2 x^2}}+\frac {3\ 2^{-7-2 n} d^2 e^{-\frac {4 a}{b}} \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac {4 (a+b \text {arcsinh}(c x))}{b}\right )}{c \sqrt {1+c^2 x^2}}+\frac {15\ 2^{-7-n} d^2 e^{-\frac {2 a}{b}} \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (1+n,-\frac {2 (a+b \text {arcsinh}(c x))}{b}\right )}{c \sqrt {1+c^2 x^2}}-\frac {15\ 2^{-7-n} d^2 e^{\frac {2 a}{b}} \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^n \left (\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (1+n,\frac {2 (a+b \text {arcsinh}(c x))}{b}\right )}{c \sqrt {1+c^2 x^2}}-\frac {3\ 2^{-7-2 n} d^2 e^{\frac {4 a}{b}} \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^n \left (\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (1+n,\frac {4 (a+b \text {arcsinh}(c x))}{b}\right )}{c \sqrt {1+c^2 x^2}}-\frac {2^{-7-n} 3^{-1-n} d^2 e^{\frac {6 a}{b}} \sqrt {d+c^2 d x^2} (a+b \text {arcsinh}(c x))^n \left (\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (1+n,\frac {6 (a+b \text {arcsinh}(c x))}{b}\right )}{c \sqrt {1+c^2 x^2}} \]

output

5/16*d^2*(a+b*arcsinh(c*x))^(1+n)*(c^2*d*x^2+d)^(1/2)/b/c/(1+n)/(c^2*x^2+1 
)^(1/2)+2^(-7-n)*3^(-1-n)*d^2*(a+b*arcsinh(c*x))^n*GAMMA(1+n,-6*(a+b*arcsi 
nh(c*x))/b)*(c^2*d*x^2+d)^(1/2)/c/exp(6*a/b)/(((-a-b*arcsinh(c*x))/b)^n)/( 
c^2*x^2+1)^(1/2)+3*2^(-7-2*n)*d^2*(a+b*arcsinh(c*x))^n*GAMMA(1+n,-4*(a+b*a 
rcsinh(c*x))/b)*(c^2*d*x^2+d)^(1/2)/c/exp(4*a/b)/(((-a-b*arcsinh(c*x))/b)^ 
n)/(c^2*x^2+1)^(1/2)+15*2^(-7-n)*d^2*(a+b*arcsinh(c*x))^n*GAMMA(1+n,-2*(a+ 
b*arcsinh(c*x))/b)*(c^2*d*x^2+d)^(1/2)/c/exp(2*a/b)/(((-a-b*arcsinh(c*x))/ 
b)^n)/(c^2*x^2+1)^(1/2)-15*2^(-7-n)*d^2*exp(2*a/b)*(a+b*arcsinh(c*x))^n*GA 
MMA(1+n,2*(a+b*arcsinh(c*x))/b)*(c^2*d*x^2+d)^(1/2)/c/(((a+b*arcsinh(c*x)) 
/b)^n)/(c^2*x^2+1)^(1/2)-3*2^(-7-2*n)*d^2*exp(4*a/b)*(a+b*arcsinh(c*x))^n* 
GAMMA(1+n,4*(a+b*arcsinh(c*x))/b)*(c^2*d*x^2+d)^(1/2)/c/(((a+b*arcsinh(c*x 
))/b)^n)/(c^2*x^2+1)^(1/2)-2^(-7-n)*3^(-1-n)*d^2*exp(6*a/b)*(a+b*arcsinh(c 
*x))^n*GAMMA(1+n,6*(a+b*arcsinh(c*x))/b)*(c^2*d*x^2+d)^(1/2)/c/(((a+b*arcs 
inh(c*x))/b)^n)/(c^2*x^2+1)^(1/2)
 

3.6.24.2 Mathematica [A] (verified)

Time = 4.00 (sec) , antiderivative size = 529, normalized size of antiderivative = 0.84 \[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\frac {2^{-7-2 n} 3^{-1-n} d^3 e^{-\frac {6 a}{b}} \sqrt {1+c^2 x^2} (a+b \text {arcsinh}(c x))^n \left (-\frac {(a+b \text {arcsinh}(c x))^2}{b^2}\right )^{-2 n} \left (2^n b (1+n) \left (\frac {a}{b}+\text {arcsinh}(c x)\right )^{2 n} \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^n \Gamma \left (1+n,-\frac {6 (a+b \text {arcsinh}(c x))}{b}\right )+3^{2+n} b e^{\frac {2 a}{b}} (1+n) \left (\frac {a}{b}+\text {arcsinh}(c x)\right )^{2 n} \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^n \Gamma \left (1+n,-\frac {4 (a+b \text {arcsinh}(c x))}{b}\right )+5\ 2^n 3^{2+n} b e^{\frac {4 a}{b}} (1+n) \left (\frac {a}{b}+\text {arcsinh}(c x)\right )^n \left (-\frac {(a+b \text {arcsinh}(c x))^2}{b^2}\right )^n \Gamma \left (1+n,-\frac {2 (a+b \text {arcsinh}(c x))}{b}\right )-e^{\frac {6 a}{b}} \left (5\ 2^n 3^{2+n} b e^{\frac {2 a}{b}} (1+n) \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^n \left (-\frac {(a+b \text {arcsinh}(c x))^2}{b^2}\right )^n \Gamma \left (1+n,\frac {2 (a+b \text {arcsinh}(c x))}{b}\right )+3^{2+n} b e^{\frac {4 a}{b}} (1+n) \left (\frac {a}{b}+\text {arcsinh}(c x)\right )^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{2 n} \Gamma \left (1+n,\frac {4 (a+b \text {arcsinh}(c x))}{b}\right )+2^n \left (-5 2^{3+n} 3^{1+n} (a+b \text {arcsinh}(c x)) \left (-\frac {(a+b \text {arcsinh}(c x))^2}{b^2}\right )^{2 n}+b e^{\frac {6 a}{b}} (1+n) \left (\frac {a}{b}+\text {arcsinh}(c x)\right )^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{2 n} \Gamma \left (1+n,\frac {6 (a+b \text {arcsinh}(c x))}{b}\right )\right )\right )\right )}{b c (1+n) \sqrt {d+c^2 d x^2}} \]

input

Integrate[(d + c^2*d*x^2)^(5/2)*(a + b*ArcSinh[c*x])^n,x]
 

output

(2^(-7 - 2*n)*3^(-1 - n)*d^3*Sqrt[1 + c^2*x^2]*(a + b*ArcSinh[c*x])^n*(2^n 
*b*(1 + n)*(a/b + ArcSinh[c*x])^(2*n)*(-((a + b*ArcSinh[c*x])/b))^n*Gamma[ 
1 + n, (-6*(a + b*ArcSinh[c*x]))/b] + 3^(2 + n)*b*E^((2*a)/b)*(1 + n)*(a/b 
 + ArcSinh[c*x])^(2*n)*(-((a + b*ArcSinh[c*x])/b))^n*Gamma[1 + n, (-4*(a + 
 b*ArcSinh[c*x]))/b] + 5*2^n*3^(2 + n)*b*E^((4*a)/b)*(1 + n)*(a/b + ArcSin 
h[c*x])^n*(-((a + b*ArcSinh[c*x])^2/b^2))^n*Gamma[1 + n, (-2*(a + b*ArcSin 
h[c*x]))/b] - E^((6*a)/b)*(5*2^n*3^(2 + n)*b*E^((2*a)/b)*(1 + n)*(-((a + b 
*ArcSinh[c*x])/b))^n*(-((a + b*ArcSinh[c*x])^2/b^2))^n*Gamma[1 + n, (2*(a 
+ b*ArcSinh[c*x]))/b] + 3^(2 + n)*b*E^((4*a)/b)*(1 + n)*(a/b + ArcSinh[c*x 
])^n*(-((a + b*ArcSinh[c*x])/b))^(2*n)*Gamma[1 + n, (4*(a + b*ArcSinh[c*x] 
))/b] + 2^n*(-5*2^(3 + n)*3^(1 + n)*(a + b*ArcSinh[c*x])*(-((a + b*ArcSinh 
[c*x])^2/b^2))^(2*n) + b*E^((6*a)/b)*(1 + n)*(a/b + ArcSinh[c*x])^n*(-((a 
+ b*ArcSinh[c*x])/b))^(2*n)*Gamma[1 + n, (6*(a + b*ArcSinh[c*x]))/b]))))/( 
b*c*E^((6*a)/b)*(1 + n)*Sqrt[d + c^2*d*x^2]*(-((a + b*ArcSinh[c*x])^2/b^2) 
)^(2*n))
 

3.6.24.3 Rubi [A] (verified)

Time = 0.75 (sec) , antiderivative size = 441, normalized size of antiderivative = 0.70, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {6206, 3042, 3793, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \left (c^2 d x^2+d\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx\)

\(\Big \downarrow \) 6206

\(\displaystyle \frac {d^2 \sqrt {c^2 d x^2+d} \int (a+b \text {arcsinh}(c x))^n \cosh ^6\left (\frac {a}{b}-\frac {a+b \text {arcsinh}(c x)}{b}\right )d(a+b \text {arcsinh}(c x))}{b c \sqrt {c^2 x^2+1}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {d^2 \sqrt {c^2 d x^2+d} \int (a+b \text {arcsinh}(c x))^n \sin \left (\frac {i a}{b}-\frac {i (a+b \text {arcsinh}(c x))}{b}+\frac {\pi }{2}\right )^6d(a+b \text {arcsinh}(c x))}{b c \sqrt {c^2 x^2+1}}\)

\(\Big \downarrow \) 3793

\(\displaystyle \frac {d^2 \sqrt {c^2 d x^2+d} \int \left (\frac {1}{32} \cosh \left (\frac {6 a}{b}-\frac {6 (a+b \text {arcsinh}(c x))}{b}\right ) (a+b \text {arcsinh}(c x))^n+\frac {3}{16} \cosh \left (\frac {4 a}{b}-\frac {4 (a+b \text {arcsinh}(c x))}{b}\right ) (a+b \text {arcsinh}(c x))^n+\frac {15}{32} \cosh \left (\frac {2 a}{b}-\frac {2 (a+b \text {arcsinh}(c x))}{b}\right ) (a+b \text {arcsinh}(c x))^n+\frac {5}{16} (a+b \text {arcsinh}(c x))^n\right )d(a+b \text {arcsinh}(c x))}{b c \sqrt {c^2 x^2+1}}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {d^2 \sqrt {c^2 d x^2+d} \left (\frac {5 (a+b \text {arcsinh}(c x))^{n+1}}{16 (n+1)}+b 2^{-n-7} 3^{-n-1} e^{-\frac {6 a}{b}} (a+b \text {arcsinh}(c x))^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (n+1,-\frac {6 (a+b \text {arcsinh}(c x))}{b}\right )+3 b 2^{-2 n-7} e^{-\frac {4 a}{b}} (a+b \text {arcsinh}(c x))^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (n+1,-\frac {4 (a+b \text {arcsinh}(c x))}{b}\right )+15 b 2^{-n-7} e^{-\frac {2 a}{b}} (a+b \text {arcsinh}(c x))^n \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (n+1,-\frac {2 (a+b \text {arcsinh}(c x))}{b}\right )-15 b 2^{-n-7} e^{\frac {2 a}{b}} (a+b \text {arcsinh}(c x))^n \left (\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (n+1,\frac {2 (a+b \text {arcsinh}(c x))}{b}\right )-3 b 2^{-2 n-7} e^{\frac {4 a}{b}} (a+b \text {arcsinh}(c x))^n \left (\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (n+1,\frac {4 (a+b \text {arcsinh}(c x))}{b}\right )-b 2^{-n-7} 3^{-n-1} e^{\frac {6 a}{b}} (a+b \text {arcsinh}(c x))^n \left (\frac {a+b \text {arcsinh}(c x)}{b}\right )^{-n} \Gamma \left (n+1,\frac {6 (a+b \text {arcsinh}(c x))}{b}\right )\right )}{b c \sqrt {c^2 x^2+1}}\)

input

Int[(d + c^2*d*x^2)^(5/2)*(a + b*ArcSinh[c*x])^n,x]
 

output

(d^2*Sqrt[d + c^2*d*x^2]*((5*(a + b*ArcSinh[c*x])^(1 + n))/(16*(1 + n)) + 
(2^(-7 - n)*3^(-1 - n)*b*(a + b*ArcSinh[c*x])^n*Gamma[1 + n, (-6*(a + b*Ar 
cSinh[c*x]))/b])/(E^((6*a)/b)*(-((a + b*ArcSinh[c*x])/b))^n) + (3*2^(-7 - 
2*n)*b*(a + b*ArcSinh[c*x])^n*Gamma[1 + n, (-4*(a + b*ArcSinh[c*x]))/b])/( 
E^((4*a)/b)*(-((a + b*ArcSinh[c*x])/b))^n) + (15*2^(-7 - n)*b*(a + b*ArcSi 
nh[c*x])^n*Gamma[1 + n, (-2*(a + b*ArcSinh[c*x]))/b])/(E^((2*a)/b)*(-((a + 
 b*ArcSinh[c*x])/b))^n) - (15*2^(-7 - n)*b*E^((2*a)/b)*(a + b*ArcSinh[c*x] 
)^n*Gamma[1 + n, (2*(a + b*ArcSinh[c*x]))/b])/((a + b*ArcSinh[c*x])/b)^n - 
 (3*2^(-7 - 2*n)*b*E^((4*a)/b)*(a + b*ArcSinh[c*x])^n*Gamma[1 + n, (4*(a + 
 b*ArcSinh[c*x]))/b])/((a + b*ArcSinh[c*x])/b)^n - (2^(-7 - n)*3^(-1 - n)* 
b*E^((6*a)/b)*(a + b*ArcSinh[c*x])^n*Gamma[1 + n, (6*(a + b*ArcSinh[c*x])) 
/b])/((a + b*ArcSinh[c*x])/b)^n))/(b*c*Sqrt[1 + c^2*x^2])
 

3.6.24.3.1 Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3793

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In 
t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f 
, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
 

rule 6206

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((d_) + (e_.)*(x_)^2)^(p_.), 
x_Symbol] :> Simp[(1/(b*c))*Simp[(d + e*x^2)^p/(1 + c^2*x^2)^p]   Subst[Int 
[x^n*Cosh[-a/b + x/b]^(2*p + 1), x], x, a + b*ArcSinh[c*x]], x] /; FreeQ[{a 
, b, c, d, e, n}, x] && EqQ[e, c^2*d] && IGtQ[2*p, 0]
 

3.6.24.4 Maple [F]

\[\int \left (c^{2} d \,x^{2}+d \right )^{\frac {5}{2}} \left (a +b \,\operatorname {arcsinh}\left (c x \right )\right )^{n}d x\]

input

int((c^2*d*x^2+d)^(5/2)*(a+b*arcsinh(c*x))^n,x)
 

output

int((c^2*d*x^2+d)^(5/2)*(a+b*arcsinh(c*x))^n,x)
 

3.6.24.5 Fricas [F]

\[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\int { {\left (c^{2} d x^{2} + d\right )}^{\frac {5}{2}} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{n} \,d x } \]

input

integrate((c^2*d*x^2+d)^(5/2)*(a+b*arcsinh(c*x))^n,x, algorithm="fricas")
 

output

integral((c^4*d^2*x^4 + 2*c^2*d^2*x^2 + d^2)*sqrt(c^2*d*x^2 + d)*(b*arcsin 
h(c*x) + a)^n, x)
 

3.6.24.6 Sympy [F(-1)]

Timed out. \[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\text {Timed out} \]

input

integrate((c**2*d*x**2+d)**(5/2)*(a+b*asinh(c*x))**n,x)
 

output

Timed out
 

3.6.24.7 Maxima [F]

\[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\int { {\left (c^{2} d x^{2} + d\right )}^{\frac {5}{2}} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{n} \,d x } \]

input

integrate((c^2*d*x^2+d)^(5/2)*(a+b*arcsinh(c*x))^n,x, algorithm="maxima")
 

output

integrate((c^2*d*x^2 + d)^(5/2)*(b*arcsinh(c*x) + a)^n, x)
 

3.6.24.8 Giac [F(-2)]

Exception generated. \[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\text {Exception raised: TypeError} \]

input

integrate((c^2*d*x^2+d)^(5/2)*(a+b*arcsinh(c*x))^n,x, algorithm="giac")
 

output

Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const 
index_m & i,const vecteur & l) Error: Bad Argument Value
 

3.6.24.9 Mupad [F(-1)]

Timed out. \[ \int \left (d+c^2 d x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^n \, dx=\int {\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}^n\,{\left (d\,c^2\,x^2+d\right )}^{5/2} \,d x \]

input

int((a + b*asinh(c*x))^n*(d + c^2*d*x^2)^(5/2),x)
 

output

int((a + b*asinh(c*x))^n*(d + c^2*d*x^2)^(5/2), x)